In this activity, we are going to use tree diagrams to solve probability questions.
Given the following tree diagram, how could we find the probability that a bus is late on both days?
We want the probability that the bus is late on Monday and on Tuesday, i.e. the probability of the green path:
Anytime we are finding the probability of something 'and' something happening or the probability on the same path on the tree diagram, we multiply the probabilities:
P(late and late) = 0.3 x 0.3 = 0.09
Now, how could we use this to find the probability that the bus will not be late on both days?
Let's remember that that the probability of something not happening is 1 minus the probability of it happening:
P(not A) = 1 - P(A)
So the probability that the bus will not be late on both days can be found by subtracting the probability that it will be late on both days from 1:
P(won't be late both days) = 1 - P(late on both) = 1 - 0.09 = 0.91
Ready to put this into practice?